Axuda do LibreOffice 25.2
Returns the number of date or time intervals between two given date values.
DateDiff (interval As String, date1 As Date, date2 As Date [, firstDayOfWeek As Integer [, firstWeekOfYear As Integer]]) As Double
Un número.
interval - A string expression from the following table, specifying the date or time interval.
date1, date2 - The two date values to be compared.
firstdayofweek: An optional parameter that specifies the starting day of a week.
| firstdayofweek value | Explicación | 
|---|---|
| 0 | Usar o valor predeterminado do sistema | 
| 1 | Domingo (predefinido) | 
| 2 | Luns | 
| 3 | Martes | 
| 4 | Mércores | 
| 5 | Xoves | 
| 6 | Venres | 
| 7 | Sábado | 
firstweekofyear: An optional parameter that specifies the starting week of a year.
| firstweekofyear value | Explicación | 
|---|---|
| 0 | Usar o valor predeterminado do sistema | 
| 1 | Semana 1 é a primeira semana de xaneiro (predefinido) | 
| 2 | Semana 1 é a primeira semana que contén catro días ou máis do ano en curso | 
| 3 | Semana 1 é a primeira semana que só contén días do novo ano. | 
Sub example_datediff
    MsgBox DateDiff("d", #1/1/2005#, #2005-12-31#)
End Sub